The post How To Calculate The Cutting Length Of Circular Stirrup appeared first on Surveying & Architects.
]]>Now, let us calculate the cutting length of the circular stirrup for the below-given drawing.
Diameter of circular column D = 450mm
Clear cover = 40mm.
The diameter of stirrup d = 8mm.
= [2πr + ( 2nos. × hook length ) – ( 2nos. × hook bend. ) ]
= [ 2πr +( 2nos. × 10d ) – ( 2nos. × 2d )
d = diameter of the stirrup.
r = radius of the centerline of the circular stirrup ( as shown in the drawing).
First, we will calculate the value of r from the given data.
r = [ (1/2 × diameter of column ) – clear cover – ( 1/2 × diameter of stirrup bar )]
r = [ (1/2 × 450mm ) – 40mm – ( 1/2 × 8mm ) ]
r = [ 225mm – 40mm – 4mm ]
= [ ( 2 × π × 181mm ) + ( 2nos × 10d ) – ( 2nos. × 2d ) ]
= [ ( 2 × 3.142 × 181mm ) + ( 2nos. × 10 × 8mm ) – ( 2nos. × 2 × 8mm. )]
= [ 1137.4 mm + 160mm – 32mm ]
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]]>The post Bar Bending Schedule Of Footing appeared first on Surveying & Architects.
]]>Let us prepare the bar bending schedule of the footing for the below-given drawing.
footing length = 2000 mm., width = 1500 mm. , depth = 300 mm.
rebar diameter = 12 mm. spacing =150 mm, cover = 50 mm on all the sides.
No. of bars along x-direction
= [ {( footing length ) – ( 2 × cover )} ÷ spacing ] + 1
= [ {( 2000 mm.) – ( 2 × 50 mm.)} ÷ 150 mm.] +1
= [ { 1900 mm } ÷ 150 mm. ] +1
= 12.67 +1
( by rounding off )
No. of bars along y-direction
= [ {( footing width ) – ( 2 × cover )} ÷ spacing ] + 1
= [ {( 1500 mm.) – ( 2 × 50 mm.)} ÷ 150 mm.] +1
= [ { 1400 mm } ÷ 150 mm. ] +1
= 9.33 +1
Cutting length of the bar along the x-direction
= [ {bar length in x – axis } +{ 2 nos. ×( L- bend length)}] – 2nos.× ( 2 times bar dia. for 90° bend.)
=[ { footing length – 2 × cover } + 2nos.×{ footing height – 2 × cover}] – 2× ( 2 × bar dia. )
= [ { 2000 mm. – 2 × 50 mm. } + 2 × { 300 mm. – 2 × 50 mm. } ] – 2 × ( 2 × 12 mm.)
= [ 1900 mm. + 400 mm ] – 48 mm.
= 2300 mm – 48 mm
= 2252 mm. i.e. 2.252 m.
Cutting length of the bar along the y -direction
= [ {bar length in y – axis } +{ 2 nos. ×( L- bend length)}] – 2nos.× ( 2 times bar dia. for 90° bend.)
=[ { footing width – 2 × cover } + 2nos.×{ footing height – 2 × cover}] – 2× ( 2 × bar dia. )
= [ { 1500 mm. – 2 × 50 mm. } + 2 × { 300 mm. – 2 × 50 mm. } ] – 2 × ( 2 × 12 mm.)
= [ 1400 mm. + 400 mm ] – 48 mm.
= 1800 mm – 48 mm
= 1752 mm. i.e. 1.752 m.
Longitudinal bar dia. d = 16 mm., no. of bars = 4 no.
Lateral ties bar dia. d1= 8 mm., spacing = 250 mm. cover =40 mm.
Column size x = 300mm & y = 230 mm.
Development length Ld = 50d
Length of the longitudinal bar
= up to ground level + GL to plinth level + plinth level to slab bottom + slab cover + Ld + L- bend in footing – distance from footing bottom.
= {1200 mm.+ 450 mm. +3000 mm.+ 20 mm + 50d + 300 mm.} – 70 mm.
={ 4670 +( 50 × 16mm )+ 300 mm } – 70 mm.
= 5770 mm – 70 mm
= 5700 mm i.e. 5.70 m.
Length of the lateral ties
= perimeter of lateral ties + total hook length – no. of bends
= 2sides × ( x – 2 × cover ) + 2 sides × ( y – 2 × cover ) +( 2nos × hook length) – (3 nos. × bend )
( Here, we have taken hook length = 10d1 for 135°∠ & bend = 2d1 for 90°∟)
={ [ 2 × (300mm – 2× 40mm.) ]+[ 2 × ( 230 mm – 2 × 40 mm.) ] } + { 2 × 10 × 8mm }- {3 × 2 × 8mm }
={ [ 2 × 220 mm ] + [2 × 150 mm ]} + 160 mm – 48 mm.
= {440 mm + 300 mm} + 112 mm
= 852 mm i.e. 0.852 m.
Total number of lateral ties ( stirrups )
={ [length of the longitudinal bar – (Ld + L bend over footing)] ÷ stirrup spacing } + 1
={[ 5700 mm – (50 × 16 mm + 300 mm.)] ÷ 250 mm.} + 1
= {[ 5700mm – 1100mm ] ÷ 250 mm.} + 1
= {4600 mm ÷ 250 mm.} + 1
= 18.4 + 1
= 19.4 nos.
Rounding off, the number of stirrups required = 20 nos.
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]]>The post Seven Basic Rules For Providing Lap Splice In Column And Slab appeared first on Surveying & Architects.
]]>When we extend the top bar of the column from the bottom bar, having an unequal diameter, then the lap length is calculated for the smaller dia. bar.
Lap length 50d = 50 × 16mm = 800mm. correct
Lap length 50d = 50 × 20mm = 1000mm incorrect
When we provide lapping in a column, all the rebars should be lapped in Zone-Bas shown in the drawing. The top and bottom portion of the column, i.e.zone-A ( L/4 length ) should be avoided as there will be a maximum moment in this zone due to lateral forces acting on the column.
If the length of the column is L, then the L/4 length from the top & bottom of the column is categorized as tension zone A and the center L/2 length of the column (zone B ) is considered a safe area for the lapping purpose.
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]]>The post How To Calculate The weight of Steel With Formula appeared first on Surveying & Architects.
]]>Weight of Steel calculation formula | how calculate weight of Steel | Steel calculation weight | steel calculation | weight of Steel bars formula | calculation of weight of steel plate | Steel calculation for beam | Steel calculation in slab
As we know today is the era of reinforced concrete required for all type of construction work, steel or reinforcement bar is one of the most important component of concrete required to enhance the compressive strength of any structure slab, column, beam, heavy industrial projects, power plants, pools, Bridge ,dams, Reservoir and etc.
Every construction projects require estimating of Steel quantity, weight of Steel calculation is not only crucial and important for projects it is also needed in the transport sector and for purchasing average quantity of steel, for Steel calculation weight you need to know weight of Steel bars formula that helping you determining and estimating the weight of round bar, steel plate, Steel pipe, I beam, H beam, slab and column.
Generally weight of Steel is equal to multiplication of volume and their density, such as mass = volume × density, density of steel is around 7850 kg/m3, regarding this, “how calculate weight of Steel”, you can do weight of Steel calculation by using the various formula – D^2/162 in kg/m, D^2/533 in kg/ft. or mass = volume × 7850 kg/m3 to determine and estimating the required quantity or weight of Steel.
There are various Shape Of Steel bars or sheets available in market and used for different construction type are round/ circular solid bars, square shaped solidi bars, hexagonal solid bars, I beam, H beam and etc., used for different structures like slab, beam and column in residential and commercial houses.
Steel calculation is helping you in determining the approximate required quantity or weight of Steel bars needed for your construction projects, it also helps in transporting sector for uplifting the materials, it makes progressive in development of projects and required quantity of steel available up to the time, can’t delete in your projects.
Regarding this, “weight of Steel calculation”, you can calculate weight of different types of Steels bars, round solid bars, square shaped solid bars, hexagonal solid bar, metal sheets, H- beam, I- beam in their standard units kg/ m, kg/ ft. or lbs./ ft. by using standard formula, such as mass = volume × density, D^2/162 in kg/ m, D^2/533 in kg/ ft, or D^2 × 0.004143 in lbs./ ft. for round/ circular solid steel bars.
Regarding this, “Steel calculation weight”, you can calculate weight of different types of Steels bars, round solid bars, square shaped solid bars, hexagonal solid bar, metal sheets, H- beam, I- beam in their standard units kg/ m, kg/ ft or lbs./ ft. by using standard formula, such as mass = volume × density, D^2/162 in kg/ m, D^2/533 in kg/ ft, or D^2 × 0.004143 in lbs./ ft. for round/ circular solid steel bars.
To determine and calculator the weight of steel, you need to do Steel calculation by multiplying the total length of Steel bar with the following unit weight in kilogram per meter (kg/m)–
● 8mm steel bar = 0.395 kg/m
● 10mm steel bar = 0.617 kg/m
● 12mm steel bar = 0.888 kg/m
● 16mm steel bar = 1.580 kg/m
● 20mm steel bar = 2.469 kg/m
● 25mm steel bar = 3.858 kg/m
● 8mm steel bar = 0.120 kg/ft.
● 10mm steel bar = 0.188 kg/ft.
● 12mm steel bar = 0.270 kg/ft.
● 16mm steel bar = 0.480 kg/ft.
● 20mm steel bar = 0.750 kg/ft.
● 25mm steel bar = 1.172 kg/ft.
Steel weight in kg = D^2/162.28 × L × Quantity, where D = diameter of solid round bar in mm, L = length of Steel bar in meter and Q = quantity of steel.
Steel weight in tons = steel weight in kg/1000
For example:- calculate the weight of metal sheets of dimension 96″ × 36″ × 1″
Given, length of sheet = 96″
width of metal sheet = 36″
Thickness of metal sheet = 1″
Volume of sheet = 96″× 36″ × 1″ = 3456 cubic inch or 2 cubic feet or 0.0566 cubic meters
Density of steel = 7850 kg/m3
Weight of steel = volume × density
Mass = 0.0566m3 × 7850kg/m3 = approx. 445 kgs,
Hence weight of metal sheet = 445 kgs
Weight of Steel generally depends on their density, strength and their grade, regarding this, “how to calculate weight of Steel”, generally you can calculate weight of Steel by measuring the length width and thickness of metal sheet multiply to get volume, such as volume = length × width × thickness, then after volume is multiply to density of steel to get weight of Steel in their standard units, such as mass = volume × density.
How calculate weight of steel- you can calculate weight of Steel by using standard formulas in following steps-
● Measures the length width and thickness of metal sheets, assume a metal sheet is 96″ in length by 36″ wide by 1 inch thick
● Calculate volume of metal sheets by multiplying length width and thickness, volume of sheet = 96″× 36″ × 1″ = 3456 cubic inch or 2 cubic feet or 0.0566 cubic meters
● Calculate weight of metal sheet by multiplying volume and their density, such as weight of steel = volume × density, Mass = 0.0566m3 × 7850kg/m3 = approx. 445 kgs, hence weight of metal sheet = 445 kgs.
There are several Steel calculation formula for estimating approximate Steel quantity required for RCC concrete structure residential and commercial building and for calculating weight of round/ circular solid bars, square shaped solidi bars, hexagonal solid bars, I beam, H beam steel. Formula for steel calculation make easy process to determining the steel weight.
Weight of Steel bars formula/ weight of Steel calculation formula are following:-
● Round/ circular solid bars = D^2 × 0.006165 kg/ m
● Round/ circular solid bars = D^2 × 0.001876 kg/ ft
● Round/ circular solid bars = D^2 × 0.004143 lbs/ ft
● Hexagonal solid bars = D^2 × 0.006798 kg/m
● Hexagonal solid bars = D^2 × 0.006165 lbs/ft
● Square shaped solid bars = (size in mm)^2 × 0.00785 kg/m
● Square shaped solid bars = (size in mm)^2 × 0.00527 lbs/ ft
● Weight of rectangular metal sheet = length × width × thickness × density
Weight of Steel plate or sheet generally depends on their density, strength and their grade, regarding this, “calculation of weight of Steel plate”, generally you can calculate weight of Steel plate or sheet by measuring the length width and thickness of metal sheet multiply to get volume, such as volume = length × width × thickness, then after volume is multiply to density of steel to get weight of Steel plate in their standard units, such as mass = volume × density.
Calculation of weight of steel plate- you can calculate weight of Steel plate or sheet by using standard formulas in following steps-
● Measures the length width and thickness of steel plate or sheets, assume a metal sheet is 96″ in length by 36″ wide by 0.5 inch thick
● Calculate volume of metal sheets by multiplying length width and thickness, volume of sheet = 96″× 36″ × 0.5″ = 1738 cubic inch or 1 cubic feet or 0.0283 cubic meters
● Calculate weight of steel plate or sheet by multiplying volume and their density, such as weight of steel = volume × density, Mass = 0.0283m3 × 7850kg/m3 = approx. 222 kgs, hence weight of metal sheet = 223 kgs.
Weight of steel plate – kg/m2:- weight of steel plate or sheet calculated in Kilogram per square metre (kg/m2), generally 2 mm thick metal sheet weight around 12.6 kg/m2, for 5 mm thick, it could be 39.3 kg/m2, for 10 mm thick, it could be 78.5 kg/m2, for 15 mm thick, it could be 118 kg/m2, for 20 mm thick, it could be 157 kg/m2 and for 5 mm thick metal plate or sheet, it could be weight around 196 kg/m2.
Weight of round/ circular steel bars generally depends on their density, strength and their grade, regarding this, “calculation of weight of round Steel bar”, generally you can calculate weight of round Steel bar by multiplying the total length of Steel bar with the D^2/162.28 common factor in kg/m or with D^2/533 common factor in kg/ft, where D is diameter of round bar in millimeter.
Using this formula for steel weight in kg = D^2/162.28 × L × Quantity, where D = diameter of solid round bar in mm, L = length of Steel bar in meter and Q = quantity of steel, weight of 10mm steel bar = (10 × 10/162.28) × 12 = 7.394 kgs, hence weight of 10mm round bar of 12 meter length is around 7.394 kgs.
Steel weight in tons = steel weight in kg/1000, put this values 7.394kg/1000 = 0.0074 MT (metric tons).
Using this formula for steel weight in kg = D^2/162.28 × L × Quantity, where D = diameter of solid round bar in mm, L = length of Steel bar in meter and Q = quantity of steel, weight of 10mm steel bar = (12 × 12/162.28) × 12 = 10.648 kgs, hence weight of 12mm round bar of 12 meter length is around 10.648 kgs.
Steel weight in tons = steel weight in kg/1000, put this values 10.648kg/1000 = 0.0106 MT (metric tons).
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