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]]>This article is about How to prepare bar bending schedule for Slab
To preparing bar bending schedule for a Slab. there are some criteria & assumptions that require to be met Let’s get started.
you should know the normal forces action on a Slab.
If you see the shear force and bending moment diagram, the slab has high moments at center and less at ends. The shear force is maximum at the ends while at the center shear force is zero or minimum.
Bar bending schedule is used by different kind of peoples and officials on construction site which is given below:
In construction site all estimation and costing operation is the responsibilities of quantity surveyor. The bar bending schedule gives the details to quantity surveyor for finding out the number of steel its type, size and shape. Contractor are using bar bending schedule (BBS) for ordering the steel bar for proceeding the construction. Steel fixer using bar bending schedule (BBS) for doing their work or installing the bar in column, beam or slab according to the bar bending schedule (BBS) that how much cut length or bending of bar will be needed and which size of steel should be use. The inspector and clerks of construction refers to the BBS to make are that the reinforcement work in the field is in proper with the design reinforcement as per drawing.
Details of Slab
Generally, there are five steps for preparing the bar bending schedule of column these five is given below:
Number of steels = (Total length of slab ÷ spacing of bar) +1
Number of stirrups = 5000 ÷ 200 + 1
Number of stirrups = 26 numbers
Number of steels = (Total length of slab ÷ spacing of bar) +1
Number of stirrups = 5000 ÷ 200 + 1
Number of stirrups = 26 numbers
Number of steels = (Total length of slab ÷ spacing of bar) +1
Number of stirrups = 5000 ÷ 125 + 1
Number of stirrups = 41 numbers
Number of steels = (Total length of slab ÷ spacing of bar) +1
Number of stirrups = 5000 ÷ 125 + 1
Number of stirrups = 41 numbers
Length of Main bar = slab length – 2(concrete cover) + Development length (Ld) + slab Length
= 5000 – 2(25) + (12×12) + (50×12)
= 5694 mm or 5.69 m
Now we find the length of bar.
The total length of Main bar = 5694 x number of steels in slab
The total length of bar = 5694 x 26
The total length of bar = 148044 mm or 148 meter
Length of Distribution bar = slab length – 2(concrete cover) + Development length (Ld) + Overlap Length
= 5000 – 2(25) + (12×12) + (50×12)
= 5694 mm or 5.69 m
Now we find the length of bar.
The total length of Distribution bar = 5694 x number of steels in slab
The total length of Distribution bar = 5694 x 26
The total length of bar = 148044 mm or 148 meter
Total Length of extra bar = Length of extra bar – concrete cover
= 1500 – 2(25)
= 1450 mm or 1.450 meter
Now we find the length of bar.
The total length of extra bar at x- axis = 1450 x number of extra bar in slab
The total length of bar = 1450 x 41
The total length of bar = 59450 mm or 59.45 meter
Length of Extra Bar at y-axis = slab length – 2(concrete cover)
= 1500 – 2(25)
= 1450 mm or 1.40 m
Now we find the length of bar.
The total length of Extra bar = 1450 x number of extra bar in slab
The total length of bar = 1450 x 41
The total length of bar = 59450 mm or 59.45 meter
length of lapping is 50d
Lapping length = 50 x Dia of steel
Length of lapping = 50×12 = 600 mm.
We know that the length of typical steel is 12.25 m or 40 feet length
Total Length of Main Bar = 148044 m that is more than 12.25 m or 40 feet so lapping should be provided.
Length of lapping is 600 mm the result will be 148044 + 600 = 148644 m
It is mentioned already in this article, consider the points while lapping the bar. There is no one right process we can use. Just remember the lines.
length of lapping is 50d
Lapping length = 50 x Dia of steel
Length of lapping = 50×12 = 600 mm.
We know that the length of typical steel is 12.25 m or 40 feet length
Total Length of Main Bar = 148044 m that is more than 12.25 m or 40 feet so lapping should be provided.
Length of lapping is 600 mm the result will be 148044 + 600 = 148644 m
It is mentioned already in this article, consider the points while lapping the bar. There is no one right process we can use. Just remember the lines.
Number of steels = (Total length of slab ÷ spacing of bar) +1
Number of stirrups = 5000 ÷ 200 + 1
Number of stirrups = 26 numbers
Number of steels = (Total length of slab ÷ spacing of bar) +1
Number of stirrups = 5000 ÷ 200 + 1
Number of stirrups = 26 numbers
Number of steels = (Total length of slab ÷ spacing of bar) +1
Number of stirrups = 5000 ÷ 125 + 1
Number of stirrups = 41 numbers
Number of steels = (Total length of slab ÷ spacing of bar) +1
Number of stirrups = 5000 ÷ 125 + 1
Number of stirrups = 41 numbers
The bar bending schedule of column is shown below in table
S. NO | Bar Mark | Bar dia | No of bars | Length (m) | unit weight(m/kg) | weight of steel (Kg) |
1 | Main Bar | 12 | 26 | 148 | 0.888 | 3417 |
2 | Distribution Bar | 12 | 26 | 148 | 0.888 | 3417 |
3 | Extra Bar x-axis | 12 | 41 | 59.45 | 0.888 | 2164.45 |
4 | Extra Bar y-axis | 12 | 41 | 59.45 | 0.888 | 2164.45 |
Total Weight of Reinforced Concrete Slab | 11163 |
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How to create the design of different types of slabs and their reinforcement
Toward a suspended slab, there are numerous designs for enhancing the strength-to-weight ratio. In every situation, the top surface keeps on flat, and the footing is adjusted:
These slabs vary from cantilevered or Simply Supported Slabs.
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