Basic Estimation And Quantity Of Materials For Brick Wall, U.C.R. Masonry Plastering And Tiles

Basic Estimation And Quantity Of Materials For Brick Wall, U.C.R. Masonry Plastering And Tiles

 

Calculate the quantity of material for load-bearing wall with length 6 m thickness 40 cm and height 3.5 m preparation of mortar (1:6)

Volume of wall = base quantity
= b x d x t = l x h x t
= 6 x 3.5 x 0.4
= 8.4 m3

 

Standard diamension of brick with mortar = 0.2 x 0.1 x 0.1 = 0.002 m3

Number of bricks = 8.4 / 0.002 = 42.00 nos.

Actual volume of one brick = 0.19 x 0.9 x 0.9 = 1.539 x 10-3

Total volume of bricks = 4200 x 1.539 x 10-3 = 6.46 m3

Volume of mortar = 8.4 – 6.46 = 1.94

Actual volume of water required will 25 % more due to losses
= 1.94 + 25 % = 2.42 m3

Quantity of cement required
= 2.42 / 7 = 0.34 m3

1 m3 = 30 bag
0.35 x 30 = 10.5 bags say 11 bags

Quantity of sand required
= 0.35 x 6 = 2.1 m3
1 truck = 5.87 m3
Therefore 0.08 m3 = 0.35 trucks

Sr. no.
Item
Quantity
Rate
Total
1
Bricks
4200 Nos.
750/100 nos.
3150
2
Sand
1 ½ Brick
2000/truck
1000
3
cement
11 bag
110/bag
1210

5,360 Rs.

 

Learn More

Civil Site Engineer Must Know +18 Civil Engineer Tips And Trick

Partition wall with bricks

Find the estimation of material required for a building partition wall with brickwork second class, cement mortar 1:6 and base quantity 10 m3

Total volume = base quantity = 10 m3

Volume of one brick with mortar
= 0.2 x 0.1 x 0.1 = 0.002 m3

No. of bricks required = 10 / 0.002 = 5000 nos.

Actual volume of one brick
= 0.10 x 0.9 x 0.9
= 1.539 x 10-3 x 5000
= 7.69 m3 say 7.7 m3

Actual volume of mortar = 10 – 7.7 = 2.3 m3

Considering 25 % more for losses.

Actual volume of mortar required
= 2.3 + 25 % 2.3 = 2.87 m3

Quantity of cement required
=2.87 / 7 = 0.41 m3
= 0.41 x 30 = 12.3 bags say 13 bags

Quantity of sand required
= 0.41 x 6 = 2.46 m3
1 truck = 5.87 m3
2.46 m3 = ½ truck

Sr. no.
Items
Quantity
Rate
Total
1
Bricks
5000
750/1000
3750
2
Sand
½ truck
2000/truck
1000
3
Cement
1/13 bag
110/bag
1430

6,180 Rs.

 

Learn More 

How To Measure Quantity Of Sand In Truck & HAIWA

Estimate for the material required for load-bearing wall of U.C.R. masonry consider base quantity 10m3 and proportion of mortar (1:6)

Quantity of stones required = 125 % of base
Quantity = 12.5 m3

Quantity of mortar required
Considering all stones.
42 % of base quantity = 4.2 m3

Quantity of cement required
= 4.2/7 = 0.6 m3
1m3 = 30 bags
0.6m3 = 18 bags

Quantity of sand required
= 0.6 x 6 = 3.6 m3
1 truck = 5.87 m3
Therefore 3.6 m3 = 0.6 trucks = 1 truck

Sr. no.
Items
Quantity
Rate
Total
1
Stone
13 m3
275/m3
3575
2
Sand
1 truck
2000/truck
2000
3
Cement
18 bags
110/bag
1980

7,555 Rs.

Estimate the quantity of material required for plastering the area 100 m2. Mix proportion used 1:5. The thickness of plaster is 12 mm.

Volume of mortars = 100 x 12 / 10 x 100 = 1.2 m3

Considering 25 % more due to losses
= 1.2 + 2.5 % . 12 = 1.5 m3

Quantity of cement required
= 1.5 / 6
=0.25 m3
0.25 m3 = 0.25 x 30
7.5 bags = 8 bags

Quantity of sand = 0.25 x 5 = 1.25 m3
1 truck = 5.87 m3
1.25 m3 = 0.21 truck
= ½ truck

Sr. no.
Items
Quantity
Rate
Total
1
Cement
8 bags
110/bag
880
2
Sand
½ truck
2000/truck
1000

1,880 Rs.

 

Learn More 

How to Calculate Quantities Cement, Sand, Aggregate and water in 1 m3 Concrete Work

Calculate the estimate for mosaic tiles flooring over an area of 100 m2 with 20 mm thick lime.
Size of tile = 20 cm x 20 cm
Proportion of mortar = (1:2:4)

Base quantity = area = 100 m2
Size of tile = 20 cm x 20 cm
The thickness of lime base = 20 mm

Area of one tile = 20 cm x 20 cm
= 400 cm2 = 0.004 m2

Total no. of tiles required = 100 /0.04 = 25 00 nos.

Volume of lime base = 100 x (20 / 10 x 100) = 2 m3

Considering 25 % more due to looses = 2 + 25 % .2 = 2.5 m3

Quantity of cement required = 2.5 / 7 = 0.35 m3
1 m3 = 30 bags
0.35 x 30 = 10.5 bags say 11 bags

Consider 6 bags of cement for 100 m2 surface for slurry
= total quantity = 10.5 +6 = 16.5 say 17 bags

Quantity of lime required = 0.35 x 2 = 0.7 m3
1 m3 = 30 bags
7 m3 = 21 bags

Quantity of sand required = 0.35 x 4 = 1.4 m3 = ½ truck

Sr.no.
Items
Quantity
Rate
Total
1
Tiles
2500
750/brass
13020
2
Cement
17 bags
110/bag

Learn More 

1. Calculation Method For Find Out The Overlapping Length Of Beam, Column And Slab

2. Bar Bending Schedule For Slab And Estimation Of Steel Reinforcement In Slab

3. How To Calculate The weight of Steel With Formula

4. How to calculate the cutting length of reinforcement bars in circular R.C.C slab

To get more information, Visit Our Official website
Land Surveying & Architects

JOIN US & LIKE OUR OFFICIAL FACEBOOK PAGE

THANKS.