Rate Analysis of Brickwork And Brick Masonry
Here we discuss the rate analysis of the brickwork or brick masonry in the superstructure brick size.
The standard size of a brick is 19cm by 9cm by 9cm without mortar.
The standard size of brick is increased 1cm with mortar, so 20cm by 10cm by 10cm.
Problem
Find the rate analysis of firstclass brickwork in cement mortar where the ratio is 1 to 6 in superstructure with the standard size of brick as above (19cm x 9cm x 9cm)
Solution
Brick Size without mortar = 19cm x 9cm x 9cm
In meters, this is 0.19m x 0.09m x 0.09 m
With mortar, the size of brick is increased by 1cm = 20cm x 10cm x 10cm
In meters, this is 0.2m x 0.1m x 0.1m
Let’s consider 10 m^{3} of volume of brickwork.
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Step 1: Quantity of Materials Calculation
A) Volume of Brick Without Mortar = 0.19 m x 0.09 m x 0.09 m = 0.001539 = 1.539 x 10^{3} m^{3}
B) Volume of Brick With Mortar = 0.2 x 0.1 x 0.1 = 0.002 = 2 x 10^{3} m^{3}
C) We now need to find out the Quantity of Each Material:
Brick quantity without wastage = 10 divided by volume of brick with mortar = 10 / (2 x 10^{3}) = 5000 Bricks
Add 5% for brick wastage = 5/100 x 5000 = 250 bricks
Total number of bricks including wastage = 5250 bricks
Wet volume of mortar = 10 – 5000 x 1.539 x 10^{3} = 2.31 m^{3}
Add 25% mortar for frog filling (brick indentations) and wastage = 25/100 x 2.31 = 0.577 m^{3}
Adding these two amounts gives us the Total Wet Volume of the Mortar which is 2.9 m^{3}
Next is the Dry Volume of Mortar which is 30% more than the above total wet volume of the mortar = 1.30 x 2.9 = 3.77 m^{3}
Quantity of Cement = ( 3.77 / (1 + 6) ) x 1 = 0.538 m^{3}
Number of Bags of Cement = quantity of cement divided by volume (Volume of 1 bag of cement = 0.035 or 35 litres) = 0.538 / 0.035 = 15.37 (so 16 bags of cement)
Quantity of Sand = ( 3.77 / (1 + 6) ) x 6 = 3.23 m^{3}
Step 2: Example Cost Calculation
Particulars  Quantity  Rate  Per  Cost 

Materials, Cement, Sand, Bricks  16 for cement, 3.23 for sand, 5250 for bricks  350 for cement, 1350 for sand, 4500 for bricks  Kg for cement, M^{3}for sand, 1000 numbers for bricks  5600 for cement, 4360.5 for sand, 23625 for bricks 
Total Amount  33585.5  
Labor  
Head mason  ½ numbers  600  Per day  300 
Mason  10 numbers  500  Per day  5000 
Worker A  10 numbers  300  Per day  3000 
Worker B  10 numbers  250  Per day  2500 
Other  2  200  Per day  400 
Total Amount  11200  
Total Cost (Materials + Labor)  44785.5 
Add 1.5% for water cost = 1.5/100 x 44785.5 = 671.8
Add 1.5% for tools and plants = 1.5/100 x 44785.5 = 671.8
Add 3% for lumpsum = 3/100 x 44785.5 = 1343.6
Add 10% for contractor’s profit = 10/100 x 44785.5 = 4478.55
Add these four to the total = Grand Total = 51951.3
Rate per m^{3} = 51951.3/10 = 5195.13
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