How To Calculate The Volume Of Concrete Triangular Pile Cap Having 3Piles
Let us calculate the volume of concrete in a triangular pile foundation having 3 nos. of the pile, as shown below.
Given data:
Pile diameter = 0.6m.( d )
No. of piles = 3 nos.
Length of pile = 16m. (h )
Depth of the pile cap = 0.9m.(D )
The volume of concrete in the piles
= 3nos.Ã—Â Ï€r2 h
Here,
r = radius of the pile.
= d Ã· 2
= 0.6m Ã· 2
= 0.3m.
h = length of the pile.
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The volume of concrete in piles
= 3nos. Ã— 3.142 Ã— (0.3m)2 Ã— 16m.
=Â 13.57 cum.
The volume of concrete in the pile cap :
The volume ofÂ pile cap concrete
=Â Surface area (A ) Ã— depth ( D )
First, let us calculate the sectional area (A1) of rectangle ABCD, as shown in the below drawing.
Area of rectangle ABCD (A1)
=LÂ Ã— B
= 2.2mÂ Ã— 2.0m
=Â 4.4 sqm.
To get the surface area ( A) of the pile cap, we have to deduct the area of triangles AEF & GDH from the rectangle area.
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Here,
Triangle AEF = triangle GDH
Area of triangle AEFÂ
= 0.5Â Ã— baseÂ Ã— height.
= 0.5Â Ã— side AEÂ Ã— side AF
Side AE
= [ ( 1/2Â Ã—side BC ) – (1/2Â Ã— side EG )]
=Â [ ( 1/2Â Ã—2m. ) – (1/2Â Ã— 0.6m. )]
= [ 1m – 0.3 m ]
=Â 0.7m.
Side AF
= side AB – side FB
= 2.2m – 0.7m
=Â 1.5m.
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I have redrawn the triangle, with the calculated length of the sides AF & AE as shown below.
Area of triangle AEF
Â = 0.5Â Ã— side AEÂ Ã— side AF
= 0.5 Ã— 0.7m Ã— 1.5m.
=Â 0.525 sqm.
The surface area of the pile cap (A )
= [area of rectangle ABCD – (2nos. Ã— area of a triangle AEF )]
= [4.4 sqm. – (2nos. Ã— 0.525sqm.)]
= [4.4 sqm. – 1.05 sqm.]
= 3.35 sqm.
Now, the concrete vol. of pile cap
= surface area (A ) Ã— depth (D )
= 3.35 sqm. Ã— 0.9m.
=Â 3.015 cum.
The total concrete volume of 3pile foundation
= The vol. of concrete in pile cap + total vol. of concrete in piles.
= 3.015 cum + 13.57 cum.
=Â Â 16.585 cum.
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