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Bar Bending Schedule Of Footing
Let us prepare the bar bending schedule of the footing for the below-given drawing.
Given dataĀ :
footing length = 2000 mm., width = 1500 mm. , depth = 300 mm.
rebar diameter = 12 mm.Ā spacing =150 mm, cover = 50 mm on all the sides.
No. of bars along x-direction
= [ {( footing length ) – ( 2Ā Ć cover )} Ć· spacing ] + 1
= [ {( 2000 mm.) – ( 2 Ć 50 mm.)} Ć· 150 mm.] +1
= [ { 1900 mm } Ć· 150 mm. ] +1
= 12.67 +1
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Ā =Ā 14 nos.
( by rounding off )
No. of bars along y-direction
= [ {( footing width ) – ( 2Ā Ć cover )} Ć· spacing ] + 1
= [ {( 1500 mm.) – ( 2 Ć 50 mm.)} Ć· 150 mm.] +1
= [ { 1400 mm } Ć· 150 mm. ] +1
= 9.33 +1
Ā =Ā 10 nos.
Cutting length of the bar along the x-direction
=Ā [Ā {bar length in x – axis } +{ 2 nos. Ć( L- bend length)}] – 2nos.Ć ( 2 times bar dia. for 90Ā° bend.)
=[ { footing length – 2 Ć cover } + 2nos.Ć{ footing height – 2 Ć cover}] – 2Ć ( 2 Ć bar dia. )
= [ { 2000 mm. – 2 Ć 50 mm. } + 2 Ć { 300 mm. – 2 Ć 50 mm. } ] – 2 Ć ( 2 Ć 12 mm.)
= [ 1900 mm. + 400 mm ] – 48 mm.
= 2300 mm – 48 mm
= 2252 mm. i.e. 2.252 m.
Cutting length of the bar along the y -direction
=Ā [Ā {bar length in y – axis } +{ 2 nos. Ć( L- bend length)}] – 2nos.Ć ( 2 times bar dia. for 90Ā° bend.)
=[ { footing width – 2 Ć cover } + 2nos.Ć{ footing height – 2 Ć cover}] – 2Ć ( 2 Ć bar dia. )
= [ { 1500 mm. – 2 Ć 50 mm. } + 2 Ć { 300 mm. – 2 Ć 50 mm. } ] – 2 Ć ( 2 Ć 12 mm.)
= [ 1400 mm. + 400 mm ] – 48 mm.
= 1800 mm – 48 mm
= 1752 mm. i.e.Ā 1.752 m.
Now, we will prepare BBS of the footing, from calculated data.
slĀ Ā Ā Ā barĀ Ā Ā dia.Ā Ā no.Ā Ā lengthĀ Ā Ā totalĀ Ā Ā weightĀ Ā Ā Ā Ā totalĀ Ā Ā
no.Ā Ā typeĀ Ā mm.Ā Ā Ā Ā Ā Ā in m.Ā Ā lengthĀ Ā in kg/mĀ Ā Ā Ā weightĀ Ā Ā Ā
Ā 1.Ā Ā x- axisĀ Ā 12Ā Ā Ā 10Ā Ā 2.252Ā Ā Ā 22.52Ā Ā Ā Ā Ā 0.89Ā Ā Ā Ā Ā 20.043Ā Ā Ā
2.Ā Ā y – axisĀ Ā 12Ā Ā Ā 14Ā Ā Ā 1.752Ā Ā Ā 24.528Ā Ā Ā 0.89Ā Ā Ā Ā Ā 21.829
Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Total weight of the bars = 41.872kgsĀ Ā Ā Ā Ā Ā Ā Ā
Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Add 2 % wastageĀ Ā Ā Ā Ā Ā = 0.837kgs
Ā Ā Ā Ā Ā Ā Ā Ā Ā The grand total of rebar for footingĀ Ā =Ā Ā 42.709 kgs.
NoteĀ : Weight of 12mm dia bar /meter isĀ 0.89 kg.
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Bar Bending Schedule of the column drawing.
Given data :
Longitudinal bar dia. d = 16 mm.,Ā no. of bars = 4 no.
Lateral ties bar dia. d1= 8 mm., spacing = 250 mm. cover =40 mm.
Column sizeĀ x = 300mmĀ & y = 230 mm.
Development length Ld = 50d
Length of the longitudinal bar
= up to ground level + GL to plinth level + plinth level to slab bottom + slab cover + Ld + L- bend in footing – distance from footing bottom.
= {1200 mm.+ 450 mm. +3000 mm.+ 20 mm + 50d + 300 mm.} – 70 mm.
={ 4670 +( 50 Ć 16mm )+ 300 mm } – 70 mm.
= 5770 mm – 70 mm
= 5700 mm i.e.Ā 5.70 m.
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Length of the lateral ties
= perimeter of lateral ties + total hook length – no. of bends
= 2sidesĀ Ć ( x – 2Ā Ć cover ) + 2 sidesĀ Ć ( y – 2Ā Ć cover ) +( 2nosĀ Ć hook length) – (3 nos.Ā Ć bend )
( Here, we have takenĀ hook length = 10d1 for 135Ā°ā Ā Ā & bend = 2d1 for 90Ā°ā)
={ [ 2Ā Ć (300mm – 2Ć 40mm.) ]+[ 2Ā Ć ( 230 mm – 2Ā Ć 40 mm.) ] } + { 2Ā Ć 10Ā Ć 8mm }- {3Ā Ć 2Ā Ć 8mm }
={ [ 2Ā Ć 220 mm ] + [2Ā Ć 150 mm ]} + 160 mm – 48 mm.
= {440 mm + 300 mm} + 112 mm
= 852 mm i.e.Ā 0.852 m.
Total number of lateral ties ( stirrups )
={ [length of the longitudinal bar – (Ld + L bend over footing)]Ā Ć· stirrup spacing } + 1
Note:Ā Ā Ld + L bend is deducted from the length as no stirrups are provided over that length.
={[ 5700 mm – (50 Ć 16 mm + 300 mm.)] Ć· 250 mm.} + 1
= {[ 5700mm – 1100mm ] Ć· 250 mm.} + 1
= {4600 mm Ć· 250 mm.} + 1
= 18.4 + 1
= 19.4 nos.
Rounding off, the number of stirrups required =Ā 20 nos.
Now, let us prepare theĀ BBS table for the column.
sl.Ā Ā barĀ Ā Ā Ā Ā Ā Ā Ā Ā Ā dia.Ā Ā Ā no.Ā Ā Ā lengthĀ Ā totalĀ Ā Ā weightĀ Ā Ā Ā totalĀ Ā
no.Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā ( mm)Ā Ā Ā Ā Ā Ā Ā Ā Ā (m.)Ā Ā Ā lengthĀ Ā Ā kg/mĀ Ā Ā weight
1.Ā longitudinalĀ Ā Ā Ā 16Ā Ā Ā Ā Ā 4Ā Ā Ā Ā 5.7Ā Ā Ā Ā Ā 22.8Ā Ā Ā Ā Ā Ā 1.58Ā Ā Ā Ā 36.024
2. lateralĀ Ā Ā Ā Ā Ā Ā Ā Ā Ā 8Ā Ā Ā Ā Ā 20Ā Ā 0.852Ā Ā Ā 17.04Ā Ā Ā Ā Ā 0.395Ā Ā Ā Ā Ā 6.732
Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Total weight of barsĀ =Ā 42.756 kgs.
Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Add 5% wastageĀ Ā Ā Ā Ā =Ā Ā 2.137 kgs.
Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Grand total of rebarsĀ =Ā Ā 44.893 kgs.Ā
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